AIPMT | 2015Atomic StructureEasy
Question
Consider 3rd orbit of He+ (Helium), using non-relativistic approach, the speed of electron in this orbit will be [given K = 9 × 109 constant, Z = 2 and h (Planck)′s Constant) = 6.6 × 10-34 Js]
Options
A.1.46 × 106 m/s
B.0.73 × 106 m/s
C.3.0 × 108 m/s
D.2.92 × 106 m/s
Solution
For H-like atoms
v = Z/n × 2.188 × 106 m/s
here Z = 2, n = 3
v = 1.46 × 106 m/s
Hence option (1)
v = Z/n × 2.188 × 106 m/s
here Z = 2, n = 3
v = 1.46 × 106 m/s
Hence option (1)
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