Trigonometric EquationHard
Question
The distance of the point (1, 0, 2) from the point of intersection of the line
and the plane
x − y + z = 16, is :
and the planex − y + z = 16, is :
Options
A.3√21
B.13
C.2√14
D.8
Solution
Point of intersection of line
= λ(let)& plane x − y + z = 16
⇒ (3λ + 2) − (4λ − 1) + (12λ + 2) = 16
⇒ λ = 1 ⇒ Q(5, 3, 14) & given P(1, 0, 2)
⇒ PQ = 13
Create a free account to view solution
View Solution FreeMore Trigonometric Equation Questions
2 sin sin =...is equal to -...If A and B be acute positive angles satisfying 3 sin2 A + 2 sin2B = 1 and 3 sin2A - 2 sin2B = 0. then-...The value of sin π/n + sin + ..... to n terms is equal to-...The solution of (2 cos x - 1) (3 + 2 cos x ) = 0 in the interval 0 ≤ θ ≤ 2π is -...