Trigonometric EquationHard
Question
The distance of the point (1, 0, 2) from the point of intersection of the line
and the plane
x − y + z = 16, is :
and the planex − y + z = 16, is :
Options
A.3√21
B.13
C.2√14
D.8
Solution
Point of intersection of line
= λ(let)& plane x − y + z = 16
⇒ (3λ + 2) − (4λ − 1) + (12λ + 2) = 16
⇒ λ = 1 ⇒ Q(5, 3, 14) & given P(1, 0, 2)
⇒ PQ = 13
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