Trigonometric EquationHard
Question
Let n be an odd integer. If sin nθ = 
, for every value of θ, then
, for every value of θ, then Options
A.bo = 1, b1 = 3
B.bo = 0, b1 = n
C.bo = - 1, b1 = n
D.bo = 0, b1 = n2 - 3n + 3
Solution
Given, sin θ =
Now, put θ = 0, we get 0 = b0
∴ sin nθ =
⇒
Taking limit as θ → 0
⇒
b1 + 0 + 0 + 0 + ......
[∵ other values becomes zero for highre powers of sin θ]
⇒
= bn
⇒ 1 = n
Now, put θ = 0, we get 0 = b0
∴ sin nθ =
⇒
Taking limit as θ → 0
⇒
b1 + 0 + 0 + 0 + ...... [∵ other values becomes zero for highre powers of sin θ]
⇒
= bn⇒ 1 = n
Create a free account to view solution
View Solution FreeMore Trigonometric Equation Questions
If cos α + cos β = 3/2 and sin α + sin α = 1/2 and θ is the arithmetic mean of α and β...A particle is acted upon by constant forces and which displace it from a point to the point The work done in standard un...A hyperbola, having the transverse axis of length 2 sinθ, is confocal with the ellipse 3x2 + 4y2 = 12. Then its equ...Given tan (πcosθ) = cot (πsinθ , then the value of cos will be-...Locus of |z - cosθ - icosθ|+|z - sinθ + isinθ| = √2(where θ is constant, i =√-1 and...