Chemical BondingHard
Question
The ionic radii (in (Ao)) of N3-, −O2- and F− are respectively :-
Options
A.1.71, 1.40 and 1.36
B.1.71, 1.36 and 1.40
C.1.36, 1.40 and 1.71
D.1.36, 1.71 and 1.40
Solution
Z e 
7N3− 7 10
= 0.7
8O2− 8 10
= 0.8
9F− 9 10
= 0.9
In case of isoelectronic species as
ratio increases ionic size decreases hence size order is
N3− > O2− > FΘ(1.71(Ao)) (1.40(Ao)) (1.36(Ao))
7N3− 7 10
= 0.7 8O2− 8 10
= 0.89F− 9 10
= 0.9In case of isoelectronic species as
ratio increases ionic size decreases hence size order is N3− > O2− > FΘ(1.71(Ao)) (1.40(Ao)) (1.36(Ao))
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