Chemical BondingHard

Question

The ionic radii (in (Ao)) of N3-, −O2- and F are respectively :-

Options

A.1.71, 1.40 and 1.36
B.1.71, 1.36 and 1.40
C.1.36, 1.40 and 1.71
D.1.36, 1.71 and 1.40

Solution

Z   e   
7N3−  7    10 = 0.7
8O2−   8    10 = 0.8
9F     9    10 = 0.9
In case of isoelectronic species as ratio increases ionic size decreases hence size order is
N3− > O2− > FΘ(1.71(Ao)) (1.40(Ao)) (1.36(Ao))

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