JEE Advanced | 2013Chemical Kinetics and Nuclear ChemistryHard
Question
In the reaction :
P + Q →R + S
the time taken for 75% reaction of P is twice the time taken for 50% reaction of P. The concentrationof Q varies with reaction time as shown in the figure. The overall order of the reaction is -
Options
A.2
B.3
C.0
D.1
Solution
For reactant ′P′
Since t75% = 2 t50%
therefore order with respect to ′P′ is ′one′
For reactant ′Q′
linear variation of concentration of ′Q′ with time suggest that order with respect to ′Q′ is zero, therefore
overall order will be = 1 + 0 = 1
Correct Option (D)
(Assuming conc. of other reactant to be very large)
Since t75% = 2 t50%
therefore order with respect to ′P′ is ′one′
For reactant ′Q′
linear variation of concentration of ′Q′ with time suggest that order with respect to ′Q′ is zero, therefore
overall order will be = 1 + 0 = 1
Correct Option (D)
(Assuming conc. of other reactant to be very large)
Create a free account to view solution
View Solution FreeTopic: Chemical Kinetics and Nuclear Chemistry·Practice all Chemical Kinetics and Nuclear Chemistry questions
More Chemical Kinetics and Nuclear Chemistry Questions
A first order reaction has a specific reaction rate of 10-2 sec–-1. How much time will it take for 20g of the reactant ...The rate constant for the reaction, 2N2O5 → 4NO2 + O2 is 3.0 × 10-4s-1. If start made with 1.0 mol L-1 of N2O...Decrease in atomic number is observed during :...First order reaction 2N2O(g) → 2N2g + O2(g)has a rate constant of 1.3 × 10-11 S-1 at 270C and 4.5 × 10-1...The colligative property is not represented by :...