JEE Advanced | 2013Coordination CompoundHard
Question
Consider the following complex ions P, Q and R ,
P = [FeF6]3- , Q = [V(H2O)6]2+ and R = [Fe(H2O)6]2+
The correct order of the complex ions, according to their spin-only magnetic moment values (in B.M.)is -
P = [FeF6]3- , Q = [V(H2O)6]2+ and R = [Fe(H2O)6]2+
The correct order of the complex ions, according to their spin-only magnetic moment values (in B.M.)is -
Options
A.R < Q < P
B.Q < R < P
C.R < P < Q
D.Q < P < R
Solution
spin only magnetic moment 
n → number of unpaired electrons
P : [FeF6]3-
F- → (weak field ligand)
ᐃ0 < P
Fe3+ ; [Ar] 3d5
number of unpaired electron = 5
Q : [V(H2O)6]2+
H2O → (weak field ligand)
ᐃ0 < P
V2+ → [Ar]3d3
number of unpaired electron = 3
R : [Fe(H2O)6]2+
H2O → (weak field ligand)
ᐃ0 < P
Fe2+ ; [Ar] 3d6
number of unpaired electron = 4
Hence, Ans (B) : Q < R < P
n → number of unpaired electrons
P : [FeF6]3-
F- → (weak field ligand)
ᐃ0 < P
Fe3+ ; [Ar] 3d5
number of unpaired electron = 5
Q : [V(H2O)6]2+
H2O → (weak field ligand)
ᐃ0 < P
V2+ → [Ar]3d3
number of unpaired electron = 3
R : [Fe(H2O)6]2+
H2O → (weak field ligand)
ᐃ0 < P
Fe2+ ; [Ar] 3d6
number of unpaired electron = 4
Hence, Ans (B) : Q < R < P
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