Coordination CompoundHardBloom L3

Question

The total number of possible isomers of the compound [CuII(NH3)4] [PtIICl4] are:

Options

A.3
B.5
C.4
D.6

Solution

Sol. [Cu(NH3)3Cl] [PtCl3(NH3)]

[CuNH3Cl3] [PtCl(NH3)3]

[CuCl4] [Pt(NH3)4]

Total four isomers

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