Coordination CompoundHardBloom L3
Question
The total number of possible isomers of the compound [CuII(NH3)4] [PtIICl4] are:
Options
A.3
B.5
C.4
D.6
Solution
Sol. [Cu(NH3)3Cl] [PtCl3(NH3)]
[CuNH3Cl3] [PtCl(NH3)3]
[CuCl4] [Pt(NH3)4]
Total four isomers
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