Trigonometric EquationHard
Question
The values of θ lying between θ = 0 and θ = π / 2 and satisfing the equation 
is,
is, Options
A.7π / 24
B.5π / 24
C.11π / 24
D.π / 24
Solution
Given,
Applying R3 → R3 - R1 and R2 → R2 - R1, we get
Applying C1 → C1 + C2
⇒
⇒ 2 + 4sin 4θ = 0
⇒ sin 4θ =
⇒ 4θ = nπ + (- 1)n
⇒ θ =
+ (-1)n+1
Clearly, θ =
are two values of θ lying between 0o and 
.
Applying R3 → R3 - R1 and R2 → R2 - R1, we get
Applying C1 → C1 + C2
⇒
⇒ 2 + 4sin 4θ = 0
⇒ sin 4θ =
⇒ 4θ = nπ + (- 1)n
⇒ θ =
+ (-1)n+1 Clearly, θ =
are two values of θ lying between 0o and .Create a free account to view solution
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