Trigonometric EquationEasy
Question
= (x3 - 2xsin-1y) 
General solution will be
Options
A.2sin-1y = (x2 - 1) + C e-x2
B.2cos-1y = (x4 + 1) + C
C.ex2 sin-1y = (x2 - x) + C
D.2cos-1y = (x2 - 1) e-x2 + C
Solution
= x3 - 2x sin-1y
+ 2x sin-1y = x3let sin-1 y = t
+ 2xt = x3I.F. = e∫2xdx = ex2
∴ solution is given by
t(ex2) = ∫x3 .ex2 dx + c let x2 = t
sin-1y ex2 =
+ c 2ndx = dt⇒ 2sin-1 y ex2 = (t.et - ∫etdt) + 2C
⇒ 2sin-1 y ex2 = (x2 - 1) ex2 + K
⇒ 2sin-1 y = (x2 -1) + k ex2
Create a free account to view solution
View Solution FreeMore Trigonometric Equation Questions
If α = 3 sin-1 and β = 3 cos-1 where the inverse trigonometric functions take only the principal values, then ...The solution of equation 13 − 4 cos2x = 12 sin x is -...The general value of θ satisfying equation tan 3 θ - tan 2θ - tanθ = 0...Value of is-...If cos 2B = , then -...