Trigonometric EquationMedium
Question
If 2 tan2 θ = sec2 θ, then the general solution of θ -
Options
A.nπ + 
B.nπ -
C.nπ ±
D.2nπ ±
Solution
2tan2 θ = sec2 θ
⇒ 2(tan2 θ) = 1 + tan2 θ
⇒ tan2 θ = tan2
θ = nπ ±
⇒ 2(tan2 θ) = 1 + tan2 θ
⇒ tan2 θ = tan2
θ = nπ ±
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