Errors in measurementHard
Question
When a piece of wire is held diametrically in a screw gauge [pitch = 1mm, number of division on circular scale = 100]. The readings obtained are as shown:
Now if we measure the same with help of vernier callipers [ 1 MSD = 1mm, 10 divisions of vernier coinciding with 9 divisions of main scale] having a negative zero error of 0.5 mm, then find which of the following figures correctly represents the reading.
Now if we measure the same with help of vernier callipers [ 1 MSD = 1mm, 10 divisions of vernier coinciding with 9 divisions of main scale] having a negative zero error of 0.5 mm, then find which of the following figures correctly represents the reading.
Options
A.
B.
C.
D.
Solution
From screw gauge z.e. = + 0.20 mm
Dia of chalk = 3.5 - 0.2 = 3.3 mm = 0.33 cm
For vernier callipers, z.e. = - 0.05 cm
Thus it must show 0.33 - 0.05 = 0.28 cm
so (a) is correct
Dia of chalk = 3.5 - 0.2 = 3.3 mm = 0.33 cm
For vernier callipers, z.e. = - 0.05 cm
Thus it must show 0.33 - 0.05 = 0.28 cm
so (a) is correct
Create a free account to view solution
View Solution FreeMore Errors in measurement Questions
Students I, II and III perform an experiment for measuring the acceleration due to gravity (g) using a simple pendulum. ...Consider a Vernier callipers in which each 1 cm on the main scale is divided into 8 equal divisions and a screw gauge wi...In an experiment to determine the acceleration due to gravity g, the formula used for the time period of a periodic mot...What is the fractional error in g calculated from T = 2π ? Given fraction errors in Tand l are + x and + y respecti...The length of a given cylindrical wire is increased by 100%. Due to the consequent decrease in diameter the change in th...