Errors in measurementEasy
Question
When a piece of wire is held diametrically in a screw gauge [pitch = 1mm, number of division on circular scale = 100]. The readings obtained are as shown:
Now if we measure the same with help of vernier callipers [ 1 MSD = 1mm, 10 divisions of vernier coinciding with 9 divisions of main scale] having a negative zero error of 0.5 mm, then find which of the following figures correctly represents the reading.
Now if we measure the same with help of vernier callipers [ 1 MSD = 1mm, 10 divisions of vernier coinciding with 9 divisions of main scale] having a negative zero error of 0.5 mm, then find which of the following figures correctly represents the reading.
Options
A.
B.
C.
D.
Solution
From screw gauge z.e. = + 0.20 mm
Dia of chalk = 3.5 - 0.2 = 3.3 mm = 0.33 cm
For vernier callipers, z.e. = - 0.05 cm
Thus it must show 0.33 - 0.05 = 0.28 cm
so (a) is correct
Dia of chalk = 3.5 - 0.2 = 3.3 mm = 0.33 cm
For vernier callipers, z.e. = - 0.05 cm
Thus it must show 0.33 - 0.05 = 0.28 cm
so (a) is correct
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