Errors in measurementMedium
Question
When both jaws of vernier callipers touch each other, zero mark of the vernier scale is right to zero mark of main scale, $4^{\text{th~}}$ mark on vernier scale coincides with certain mark on the main scale. While measuring the length of a cylinder, observer observes 15 divisions on main scale and $5^{\text{th~}}$ division of vernier scale coincides with a min scale division. Measured length of cylinder is $\_\_\_\_$ mm . (Least count of Vernier calliper $= 0.1\text{ }mm$ )
Options
A.15.4
B.15.1
C.15.5
D.15.9
Solution
Reading $= MSR + (VSR \times LC) -$ (zero Error) $= 15\text{ }mm + (5 \times 0.1\text{ }mm) - (4 \times 0.1\text{ }mm)$ Reading = 15.1 mm
$$\therefore\mathcal{l} = 15.1\text{ }mm$$
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