ElectrochemistryHard
Question
Let [∈0] denote the dimensional formula of the permittivity of vacuum. If M = mass, L = Length, T = Time and
A = electric current, then :
A = electric current, then :
Options
A.[∈0] = [M-1 L-3 T2 A]
B.[∈0] = [M-1 L-3 T4 A2]
C.[∈0] = [M-1 L-3 T -1 A-2]
D.[∈0] = [M-1 L2 T-1 A]
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