Math miscellaneousHard

Question

The correct set of four quantum numbers for the valence electron of rubidium atom (Z = 37) is -

Options

A.5, 1, 1, + 1/2
B.6, 0, 0, + 1/2
C.5, 0, 0, + 1/2
D.5, 1, 0, + 1/2

Solution

37Rb = [Kr]5s1
Its valence electron is 5s1.
so, n = 5
      l = 0 (For s orbitals)
      m = 0 (As m = - l to + l )
      s = +1/2

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