Math miscellaneousEasy
Question
The equation of the plane containing the line 2x − 5y + z = 3 ; x + y + 4z = 5, and parallel to the plane, x + 3y + 6z = 1, is :
Options
A.x + 3y + 6z = 7
B.2x + 6y + 12z = − 13
C.2x + 6y + 12z = 13
D.x + 3y + 6z = − 7
Solution
Let equation of plane parallel to x + 3y + 6z = 1 is x + 3y + 6z = λ point on line of intersection is (4, 1, 0), it also lie on plane x + 3y + 6z = λ so required plane is x + 3y + 6z = 7
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