Application of DerivativeHard

Question

The coordinates of any point P on a curve are represented by x = t2, y = t3, where t is a parameter, then equation of tangent to the curve at P is-

Options

A.6tx − 6y = t3
B.4tx + 3y = t3
C.3tx + 2y = t3
D.3tx + y = t3

Solution

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