CircleMedium
Question
The number of common tangents to the circlrs x2 + y2 = 4 and x2 + y2 - 6x - 8y = 24 is
Options
A.0
B.1
C.3
D.4
Solution
Given, x2 + y2 = 4
Centre ≡ C1 ≡ (0,0) and R1 = 2
Again, x2 + y2 - 6x - 8y - 24 = 0
and R1 = 7
Again, C1C2 = 5 = R2 - R1
Therefore, the give circles touch internally such that, they can have just one common tanrent at the point of contact.
Centre ≡ C1 ≡ (0,0) and R1 = 2
Again, x2 + y2 - 6x - 8y - 24 = 0
and R1 = 7
Again, C1C2 = 5 = R2 - R1
Therefore, the give circles touch internally such that, they can have just one common tanrent at the point of contact.
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