CircleHard
Question
Given an isosceles triangle, whose one angle is 120o and radius of its incircle = √3. Then the area of the triangle in sq. units is
Options
A.7 + 12√3
B.12-7√3
C.12 + 7√3
D.4π
Solution
ᐃ = 
b2 ...... (1)
Also
⇒ a = √3b
and ᐃ = √3s and s =
(a + 2b)
⇒ ᐃ =
(a + 2b) ...... (2)
From (1) and (2), we get ᐃ = (12 + 7√3).
b2 ...... (1)Also
⇒ a = √3band ᐃ = √3s and s =
(a + 2b) ⇒ ᐃ =
(a + 2b) ...... (2)From (1) and (2), we get ᐃ = (12 + 7√3).
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