CircleHard

Question

Given an isosceles triangle, whose one angle is 120o and radius of its incircle = √3. Then the area of the triangle in sq. units is

Options

A.7 + 12√3
B.12-7√3
C.12 + 7√3
D.

Solution

ᐃ = b2         ...... (1)
Also   ⇒ a = √3b
and   ᐃ = √3s and s = (a + 2b)
⇒   ᐃ = (a + 2b)       ...... (2)
From (1) and (2), we get ᐃ = (12 + 7√3).

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