SolutionHard
Question
When excess of SnCl2 is added to a solution of HgCl2 then final product is :-
Options
A.Hg2Cl2 (Grey)
B.Hg (White)
C.Hg2Cl2 (White)
D.Hg (Grey)
Solution
HgCl2 + SnCl2 → Hg2Cl2 + SnCl4
(White)
Hg2Cl2 + SnCl2 → Hg + SnCl4
(Grey)
(White)
Hg2Cl2 + SnCl2 → Hg + SnCl4
(Grey)
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