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Question

When excess of SnCl2 is added to a solution of HgCl2 then final product is :-

Options

A.Hg2Cl2 (Grey)
B.Hg (White)
C.Hg2Cl2 (White)
D.Hg (Grey)

Solution

HgCl2 + SnCl2 → Hg2Cl2 + SnCl4
                                            (White)
Hg2Cl2 + SnCl2 → Hg + SnCl4
                                         (Grey)

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