SolutionHard

Question

The amount of electricity that should be passed through CuSO4 solution with Cu electrodes to deposit 0.1 gram atom of Cu

Options

A.9650 Coulombs
B.96500 Coulombs
C.19300 Coulombs
D.193000 Coulombs

Solution

Weight of Cu = mole × atomic weight
                = 0.1 × 63.5 = 6.35 g
According to Faraday law
∴  Q = × 96500 cb
= 19300 cb

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