SolutionHard
Question
The amount of electricity that should be passed through CuSO4 solution with Cu electrodes to deposit 0.1 gram atom of Cu
Options
A.9650 Coulombs
B.96500 Coulombs
C.19300 Coulombs
D.193000 Coulombs
Solution
Weight of Cu = mole × atomic weight
= 0.1 × 63.5 = 6.35 g
According to Faraday law
∴ Q =
× 96500 cb
= 19300 cb
= 0.1 × 63.5 = 6.35 g
According to Faraday law
∴ Q =
× 96500 cb= 19300 cb
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