Magnetic field due to currentHard
Question
A thin circular disk of radius R is uniformly charged with density σ > 0 per unit area. The disk rotates about its axis with a uniform angular speed ω. The magnetic field at centre of the disk is :-
Options
A.μ0Rωσ
B.
μ0Rωσ
C.
σω
D.
σω
Solution
Let a ring of radius x and width dx.
Assume charge on ring is dq
Area of ring dA = 2π x dx
σ =
⇒ dq = σ2π x dx
Current due to this ring dI =
dI = ω σ x dx
Magnetic field due to ring at centre dB =
=
μ0σωdx
Magnetic field due to disc at centre
B =
μ0σω
μ0 σωR
Assume charge on ring is dq
Area of ring dA = 2π x dx
σ =
Current due to this ring dI =
dI = ω σ x dx
Magnetic field due to ring at centre dB =
=
Magnetic field due to disc at centre
B =
Create a free account to view solution
View Solution FreeMore Magnetic field due to current Questions
Current I is flowing in a conducting circular loop of radius R. It is kept in a magnetic field B which is perpendicular ...A bar magnet A of magnetic moment MA is found to oscillate at a frequency twice that of magnet B of magnetic moment MB w...A charge is moving perpendicular to a magnetic field. Its path is a :-...A short bar magnet placed with its axis at 30o with a uniform external magnetic field of 0.16T experiences a torque of m...Following charge has maximum frequency of rotation in uniform transverse magnetic field :-...