Magnetic field due to currentHard
Question
An electromagnetic wave travelling in the x-direction has frequency of 2 × 1014 Hz and electric field amplitude of 27 Vm-1. From the options given below, which one describes the magnetic field for this wave ?
Options
A.
(x, t) = (9 × 10-8 T)ĵ sin [2π(1.5 × 10-6 x − 2 × 1014 t)]
B.
(x, t) = (9 × 10-8 T)î sin [2π(1.5 × 10-8 x − 2 × 1014 t)]
C.
(x, t) = (9 × 10-8 T)
sin [2π(1.5 × 10-6 x − 2 × 1014 t)]
D.
(x, t) = (9 × 10-8 T)ĵ sin [2π(1.5 × 10-8 x − 2 × 1014 t)]
Solution
ω = 2π × 2 × 1014 Hz
B0 =
= 9 × 10-8 Tesla
Oscillation of B can be only along ĵ or k direction
∴ Option (3)
B0 =
Oscillation of B can be only along ĵ or k direction
∴ Option (3)
Create a free account to view solution
View Solution FreeMore Magnetic field due to current Questions
Following is the Biot-savart′s law in vector form :-...When a proton is released from rest in a room, it starts with an initial acceleration a0 towards west. When it is projec...An ionzed gas contains both positive and negative ions. If it is subjected simulaneously to an electric field along the ...A long cylindrical conductor with large cross section carries an electric current distributed uniformly over its cross-s...The magnetic force between wires as shown in figure is : -...