Magnetic field due to currentHard
Question
A particle having charge q enters a region of uniform magnetic field
(directed inwards) and is deflected a distance x after traveling a distance y. The magnitude of the momentum of the particle is


Options
A.
B.
C.
D.
Solution
Radius , R =
⇒ mv = qBR
where R sinθ = y ; R (1 - cos θ) = x
⇒ R =
∴ mv =

where R sinθ = y ; R (1 - cos θ) = x
⇒ R =
∴ mv =

Create a free account to view solution
View Solution FreeMore Magnetic field due to current Questions
A particle of specified charge (q/m) is projected from the origin of coordinates with initial velocity [uî + vĵ...Two insulated rings, one of slightly smaller diameter than the other, are suspended along their common diameter as shown...An α-particle and a proton are tired through the same magnetic fields which is perpendicular to their velocities . ...A coil having N turns is wound tightly in the form of a sprial with inner and outer radii a and b respectively. When a c...A coil in the shape of equilateral triangle of side 0.02 m is suspended from the vertex such that it is hanging in a ver...