Laws of MotionEasy
Question
An elevator and its load have a total mass of 800 kg. If the elevator, originally moving downward at 10 m/s, is brought to rest with constant decleration in a distance of 25 m the tension in the supporting cable will be
(g = 10m/s2) :-
(g = 10m/s2) :-
Options
A.8000 N
B.6500 N
C.11200 N
D.9600 N
Solution
by v2 = u2 - 2as
0 = 102 - 2a × 25
a = 2 m/s2 (Retardation)
For ↓ retardation :
T = m(g + a) = 800(10 + 2) = 9600 N
0 = 102 - 2a × 25
a = 2 m/s2 (Retardation)
For ↓ retardation :
T = m(g + a) = 800(10 + 2) = 9600 N
Create a free account to view solution
View Solution FreeMore Laws of Motion Questions
A metal sphere is hung by a string fixed to a wall. The forces acting on the sphere are shown are fig. Which of the foll...There are three Newton′s laws of motion namely I, II and III ; we can derive : -...A block of mass M is pulled along a horizontal friction surface by a rope of mass m. If a force P is applied at the free...Block A and C start from rest and move to the with acceleration aA = 12t m/s2 and aC = 3 m/s2 . here t is in seconds. Th...A person is standing in elevater. In which situation he finds his weight less?...