Basic Maths and Units and DimensionsMedium
Question
In the figure ABC is the cross section of a right angled prism and BCDE is the cross section of a glass slab. The value of θ so that light incident normally on the face AB does not cross the face BC is [Given sin-1 (3/5) = 37o]
Options
A.θ ≤ 37o
B.θ < 37o
C.θ ≤ 53o
D.θ < 53o
Solution
A = 90 - θ
r2 = A = 90 - θ > θC
cosθ > sinθC =
⇒ θ < cos-1
= 37o.
r2 = A = 90 - θ > θC
cosθ > sinθC =
⇒ θ < cos-1= 37o.Create a free account to view solution
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