AIPMT | 2015Basic Maths and Units and DimensionsEasy
Question
Figure below shows two paths that may be taken by a gas to go from a state A to a state C.
In process AB, 400 J of heat is added to the system and in process BC, 100 J of heat is added to the system. The heat absorbed by the system in the process AC will be :
In process AB, 400 J of heat is added to the system and in process BC, 100 J of heat is added to the system. The heat absorbed by the system in the process AC will be :
Options
A.500 J
B.460 J
C.300 J
D.380 J
Solution
In cyclic process ABCA,
ᐃUcyclic = 0
Qcyclic = Wcyclic
QAB + QBC + QCA = closed loop area.
400 + 100 + QCA =
× (2 × 10-3) × 4 × 104
400 + 100 − QAC = 40
QAC = 460 J
Hence option (2)
ᐃUcyclic = 0
Qcyclic = Wcyclic
QAB + QBC + QCA = closed loop area.
400 + 100 + QCA =
× (2 × 10-3) × 4 × 104400 + 100 − QAC = 40
QAC = 460 J
Hence option (2)
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