AIPMT | 2015Basic Maths and Units and DimensionsHard

Question

Figure below shows two paths that may be taken by a gas to go from a state A to a state C.
  
In process AB, 400 J of heat is added to the system and in process BC, 100 J of heat is added to the system. The heat absorbed by the system in the process AC will be :

Options

A.500 J
B.460 J
C.300 J
D.380 J

Solution

In cyclic process ABCA,
ᐃUcyclic = 0
Qcyclic = Wcyclic
QAB + QBC + QCA = closed loop area.
400 + 100 + QCA = × (2 × 10-3) × 4 × 104
400 + 100 − QAC = 40
QAC = 460 J
Hence option (2)

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