Continuity and DifferentiabilityHard

Question

For a real number y, let [y] denotes the greatest integest integer less than or equal to y Then, the function f(x) is

Options

A.discontinuous at some x
B.continuous at all x, but the derivative f′(x) does not exist for some x
C.f′(x) exists for all x, but the derivative f′′(x) does not exist for some x
D.f′(x) exists for all x,

Solution

Here, f(x)
Since ,we know π[(x - π)] = nπ and tan nπ = 0
∵       1 + [x]2 ≠ 0
∴       f(x) = 0 for all x
Thus, f(x) is a constant function.
∴ f′(x), f′′(x) ..... all exist for every x, their value being 0.
⇒ f′(x) exists for all x.

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