Atomic StructureHard
Question
The electron in a hydrogen atoms makes a transition n1 → n2, n1 and n2 are the principal quantum number of two states. Assume the Bohr′s model to be valid. The time period of the electrons in the initial state is eight times that in the final state. The possible values of n1 and n2 are
Options
A.n1 = 4, n2 = 2
B.n1 = 8, n2 = 2
C.n1 = 8, n2 = 1
D.n1 = 6, n2 = 3
Solution
Time period, Tn =
i.e., Tn ∝
But rn ∝ n2 and
Therefore, Tn ∝ n3
Given, Tn1 = 8Tn2
Hence, n1 = 2n2
Therefore, options (a) and (d) are correct.
i.e., Tn ∝
But rn ∝ n2 and

Therefore, Tn ∝ n3
Given, Tn1 = 8Tn2
Hence, n1 = 2n2
Therefore, options (a) and (d) are correct.
Create a free account to view solution
View Solution FreeMore Atomic Structure Questions
The de-Broglie wavelength associated with the electron in the n = 4 level is :...If an alpha particle with energy 7.7 MeV is bombarded on a thin gold foil, the closest distance from nucleus it can reac...The intensity of X-rays from collidge tube is plotted against wavelength λ as shown in the figure. The minimum wave...he decay constant of radioactive sample is λ. The half-life and mean-life of the sample are respectively given by...Two electrons are moving in orbits of two hydrogen like atoms with speeds $3 \times 10^{5}\text{ }m/s$ and $2.5 \times 1...