SemiconductorEasy
Question
In an n-p-n transistor circuit, the collector current is 10 mA. If 90 % of the electrons emitted reach the collector
Options
A.the emitter current will be 9 mA
B.the emitter current will be 11 mA
C. the base current will be 1 mA
D.the base current will be - 1 mA
Solution
Given : ic = 10mA = (0.9)ie
[Given that ic is 90% of ie]
∴ ie =
mA 
11 mA
and ib = ie - ic = (11 - 10)mA = 1 mA
[Given that ic is 90% of ie]
∴ ie =
mA 11 mA and ib = ie - ic = (11 - 10)mA = 1 mA
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