KinematicsHard
Question
The displacement x of a particle varies with time as x = ae-αt + beβt , where a, b, α and β are positive constants. The velocity of the particle will :-
Options
A.be independent of α and β
B.go on increasing with time
C.drop to zero when α = β
D.go on decreasing with time
Solution
v = a(-α)e-αt + b(β)eβt
v = - a α e-αt + bβ2eβt
a =
= aα2e-αt + bβ2eβt > 0 (always)
v = - a α e-αt + bβ2eβt
a =
= aα2e-αt + bβ2eβt > 0 (always)Create a free account to view solution
View Solution FreeMore Kinematics Questions
If R and h represent the horizontal range and maximum height respectively of an oblique projection whose start point (i....A small object of uniform density rolls up a curved surface with an initial velocity ′v′. It reaches upto a ...A body is projected horizontally from the top of a tower with initial velocity 18 ms-1. It hits the ground at angle 45o....A particle is thrown upwards from ground. It experiences resistance force which can produce retardation 2 m/s2. The rati...A body starts from rest and is uniformly accelerated for 30 s. The distance traveled in the first 10 s is x1, next 10 is...