Circular MotionMedium
Question
The second′s hand of a watch has length 6 cm. Speed of end point and magnitude of difference of velocities at two perpendicular position will be
Options
A.2π & 0 mm/s
B.2√2 & 4.44 mm/s
C.2√2 & 2π mm/s
D.2π & 2√2 π mm/s
Solution
l = 6cm, v = ?, ω = 
rad.s.
So v = ωl =
× 6 = 
cm/s = 2π mm/s
Difference = √2
cm/s = 2√2 π mm/s
rad.s.So v = ωl =
× 6 = cm/s = 2π mm/sDifference = √2
cm/s = 2√2 π mm/sCreate a free account to view solution
View Solution FreeMore Circular Motion Questions
A particle movies in a circle of radius 25 cm at two revolutions per second. The accretion of the particle in meter per ...The given figure shows a wheel of radius 1m which rotates about the axis shown in the figure. A rope is wound on this wh...A motorcyclist of mass m is to negotiate a curve of radius r with a speed v. The minimum value of the coefficient fricti...When a particle moves in a circle with a uniform speed :-...If the radii of circular paths of two particles of same masses are in the ratio of 1 : 2, then in order to have same cen...