KinematicsHard
Question
The second′s hand of a watch has length 6 cm. Speed of end point and magnitude of difference of velocities at two perpendicular position will be
Options
A.2π & 0 mm/s
B.2√2 & 4.44 mm/s
C.2√2 & 2π mm/s
D.2π & 2√2 π mm/s
Solution
l = 6cm, v = ?, ω = 
rad.s.
So v = ωl =
× 6 = 
cm/s = 2π mm/s
Difference = √2
cm/s = 2√2 π mm/s
rad.s.So v = ωl =
× 6 = cm/s = 2π mm/sDifference = √2
cm/s = 2√2 π mm/sCreate a free account to view solution
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