Math miscellaneousHard
Question
The value of ′a′ for which the system of
equation a3x + (a + 1)3y + (a + 2)3 z = 0
ax + (a + 1)y + (a + 2) z = 0
x + y + z = 0
has a non-zero solution is :-
equation a3x + (a + 1)3y + (a + 2)3 z = 0
ax + (a + 1)y + (a + 2) z = 0
x + y + z = 0
has a non-zero solution is :-
Options
A.1
B.0
C.-1
D.2
Solution
Since d1 = d2 = d3 = 0 ⇒ D1 = D2 = D3 = 0
So for non-zero solution
= 0
= 0 ⇒ a = - 1
So for non-zero solution
= 0 = 0 ⇒ a = - 1Create a free account to view solution
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