Mole ConceptEasy
Question
Calculate the N−N bond energy in N2H4 from given data.
εN-H = 393 kJ/mole
εH-H = 436 kJ/mole
ᐃHvap[N2H4(l)] = 18 kJ / mole
N2H4(l) + H2(g) → 2NH3(g) : ᐃH = -142 kJ/mole
εN-H = 393 kJ/mole
εH-H = 436 kJ/mole
ᐃHvap[N2H4(l)] = 18 kJ / mole
N2H4(l) + H2(g) → 2NH3(g) : ᐃH = -142 kJ/mole
Options
A.210 kJ/mole
B.190 kJ/mole
C.180 kJ/mole
D.150 kJ/mole
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