Nuclear Physics and RadioactivityMedium
Question
If the binding energy per nucleon in Li7 and He4 nuclei are respectively 5.60 MeV and 7.06 MeV, then energy of reaction Li7 + p → 2 2He4 is :-
Options
A.19.6 MeV
B.2.4 MeV
C.8.4 MeV
D.17.3 MeV
Solution
Energy released
= BE of product - reactant
= 2 × 4 × 7.06 - 7 × 5.60 = 17.28 MeV
= BE of product - reactant
= 2 × 4 × 7.06 - 7 × 5.60 = 17.28 MeV
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