ThermodynamicsEasy
Question
An ideal gas is taken through the cycle A → B → C → A, as shown in the figure. If the net heat supplied to the gas in the cycle is 5 J, the work done by the gas in the process C → A is
Options
A.- 5 J
B.- 10 J
C.- 15 J
D.- 20 J
Solution
ᐃWAB = pᐃV = (10) (2 - 1) = 10 J
WBC = 0 (as V = constant)
From first law of thermodynamics
dQ = dU + dW
dU = 0 (process ABCA is cyclic)
∴ ᐃQ = ᐃWAB + ᐃWBC + ᐃWCA
∴ ᐃWCA = ᐃQ - ᐃWAB - ᐃWBC
= 5 - 10 - 0 = - 5J.
WBC = 0 (as V = constant)
From first law of thermodynamics
dQ = dU + dW
dU = 0 (process ABCA is cyclic)
∴ ᐃQ = ᐃWAB + ᐃWBC + ᐃWCA
∴ ᐃWCA = ᐃQ - ᐃWAB - ᐃWBC
= 5 - 10 - 0 = - 5J.
Create a free account to view solution
View Solution FreeMore Thermodynamics Questions
The graph below shows V -P curve for three processesChose the correct statement (s)...A quantity of air (γ = 1.4) at 27oC is compressed suddenly, the temperature of the air system will :...Four curves A, B, C and D are drawn in the adjoining figure for a given amount of gas. The curves which represent adiaba...A carnot′s engine works between temperature 772oC and 27oC, the efficienty of the engine is :...The molar specific heat of the the process V ∝ T4 for CH4 at room temperature is : -...