ThermodynamicsHard
Question
A black body is at temperature if 2800 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. Then Wien constant, b = 2.88 × 106 nm-K. Then
Options
A.U1 = 0
B.U3 = 0
C.U1 > U2
D.U2 > U1
Solution
: 
Wien′s displacement law is
λm T = b (b = Wien′s constant)
∴ λm =
∴ λ = 1000 nm
Enrgy distribution with wavelength will be as follows
From the gram it is clear that
U2 > U1 [In fact U2 is maximum]
Wien′s displacement law is
λm T = b (b = Wien′s constant)
∴ λm =
∴ λ = 1000 nm
Enrgy distribution with wavelength will be as follows
From the gram it is clear that
U2 > U1 [In fact U2 is maximum]
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