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Question

An ideal gas is initially at temperature T and volume V. Its volume is increased by ᐃV due to an increase in temperature ᐃT, pressure remaing constant. The quantity δ = ᐃV /VᐃT varies with temperature as

Options

A.
B.
C.
D.

Solution

        
For an ideal gas :     pV = nRT
For       p = constant
        pᐃV = nRTᐃT
∴      
∴       or    δ =
Therefore, δ is inversly proportional to temperature T. i.e., when T increase, δ decrease and vice-versa.
Hence, δ-T grapgh will be a rectangular hyperbola as shown in the above figure.

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