ThermodynamicsHard
Question
An ideal gas is initially at temperature T and volume V. Its volume is increased by ᐃV due to an increase in temperature ᐃT, pressure remaing constant. The quantity δ = ᐃV /VᐃT varies with temperature as
Options
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Solution
For an ideal gas : pV = nRT
For p = constant
pᐃV = nRTᐃT
∴
∴
or δ = 
Therefore, δ is inversly proportional to temperature T. i.e., when T increase, δ decrease and vice-versa.
Hence, δ-T grapgh will be a rectangular hyperbola as shown in the above figure.
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