Momentum and CollisionEasy
Question
A hemispherical portion of radius R is removed from the bottom of a cylinder of radius R. The volume of the remaining cyulinder V and and mass M. It is suspended by a string in a liquid of density ρ, where is stays vertical. The upper surface of the cylinder is at a depth h bellow the liquid surfac. The force on the bottom of the cylinder by the liquid is
Options
A.Mg
B.Mg - Vρg
C.Mg + πR2hρg
D.ρg(V + πR2h)
Solution
F2 - F1 = upthrust
∴ F2 - F1 = upthrust
F2 = (p0 + ρgh) πR2 + Vρg
p0 πR2 + ρg(πR2h + V)
∴ Most appropriate option is (d).
∴ F2 - F1 = upthrust
F2 = (p0 + ρgh) πR2 + Vρg
p0 πR2 + ρg(πR2h + V)
∴ Most appropriate option is (d).
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