Momentum and CollisionHard
Question
A hemispherical portion of radius R is removed from the bottom of a cylinder of radius R. The volume of the remaining cyulinder V and and mass M. It is suspended by a string in a liquid of density ρ, where is stays vertical. The upper surface of the cylinder is at a depth h bellow the liquid surfac. The force on the bottom of the cylinder by the liquid is
Options
A.Mg
B.Mg - Vρg
C.Mg + πR2hρg
D.ρg(V + πR2h)
Solution
F2 - F1 = upthrust
∴ F2 - F1 = upthrust
F2 = (p0 + ρgh) πR2 + Vρg
p0 πR2 + ρg(πR2h + V)
∴ Most appropriate option is (d).
∴ F2 - F1 = upthrust
F2 = (p0 + ρgh) πR2 + Vρg
p0 πR2 + ρg(πR2h + V)
∴ Most appropriate option is (d).
Create a free account to view solution
View Solution FreeMore Momentum and Collision Questions
A disk A of radius r moving on perfectly smooth surface at a speed v undergoes an elastic collision with an identical st...A body of mass m = 3.513 kg is moving along the x-axis with a speed of 5.00 ms-1. The magnitude of its momentum is recor...A particle of mass m moving along x-axis has a potential energy U(x) = a + bx2 where a & b are postive constant. It ...The velocity of falling rain drop attain limited value because of : -...Two wires of same diameter of the same material having the length l and 2l. If the force F is applied on each, the ratio...