Momentum and CollisionMedium
Question
A ball of mass 2 kg dropped from a height h above a horizontal surface redounds to a height h after one bounce. The graph that relates H to h is shown in figure. If the ball was dropped from an initial height of 81 m and made ten bounces, the kinetic energy of the ball immediately after the second impact with the surface was
Options
A.320 J
B.480 J
C.640 J
D.Can′t be determined
Solution
From graph e = 
Kinetic energy of ball just after second bounce
=
m (e2u)2 = 
me4u2 = (e4) (mgH) = 
(2)(10)(81) = 320 J
Kinetic energy of ball just after second bounce
=
m (e2u)2 = me4u2 = (e4) (mgH) = (2)(10)(81) = 320 JCreate a free account to view solution
View Solution FreeMore Momentum and Collision Questions
A metal ball falls from a height of 32 metre on a steel plate. If the coefficient of restitution is 0.5, to what height ...A ball of mass ′m′, moving with uniform speed, collides elastically with another stationary ball. The incide...If the KE of a particle becomes four times its initial value, then the new momentum will be more than its initial moment...A smooth sphere A of mass elastically with an identical sphere B at rest. The velocity of A before collision is 8 m/s in...Ball A of mass 5.0 kilograms moving at 20 m/s collides with ball B of unknown mass moving at 10m/s in the same direction...