SHMEasy

Question

A linear harmonic oscillator of force constant 2 × 106 N/m and amplitude 0.01 m has a total mechanical energy of 160 J. Its

Options

A.maximum potential energy is 100 J
B.maximum kinetic energy is 100 J
C.maximum potential energy is 160 J
D.maximum potential energy is zero

Solution

kA2 = × 2 × 106 × (10-2)2 = 100J
This is basically the energy of oscillation of the particle. K, U and E at mean position (x = 0) and extreme position (x = A) are shown in figure.

∴ Correct option are (b) and (c).

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