SHMHard
Question
A linear harmonic oscillator of force constant 2 × 106 N/m and amplitude 0.01 m has a total mechanical energy of 160 J. Its
Options
A.maximum potential energy is 100 J
B.maximum kinetic energy is 100 J
C.maximum potential energy is 160 J
D.maximum potential energy is zero
Solution
kA2 = × 2 × 106 × (10-2)2 = 100JThis is basically the energy of oscillation of the particle. K, U and E at mean position (x = 0) and extreme position (x =
A) are shown in figure.
∴ Correct option are (b) and (c).
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