If $x = 5sin\left( \pi t + \frac{\pi}{3} \right)m$ represents the motion of a particle executing sim

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If $x = 5sin\left( \pi t + \frac{\pi}{3} \right)m$ represents the motion of a particle executing simple harmonic motion, the amplitude and time period of motion, respectively, are

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Sol. [Key Concept: SHM — amplitude and angular frequency from the equation] $x = 5sin\left( \pi t + \frac{\pi}{3} ight)m$Amplitude $= 5	ext{ }m$$$\begin{matrix} & \omega = \pi = \frac{2\pi}{T} \ & T = \frac{2\pi}{\pi} = 2	ext{ }s \end{matrix}$$

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