SHMMedium

Question

For a simple pendulum, having time period $T$, the variation of kinetic energy (K.E.) with time $(t)$ is represented by:

Options

A.
B.
C.
D.

Solution

Sol. [Key Concept: Simple pendulum — KE varies as sin² over time] Kinetic energy, $K = \frac{1}{2}mv^{2}$

$$\begin{matrix} & \ = \frac{1}{2}mA^{2}\omega^{2}\cos^{2}(\omega t + \phi) \\ & \ \therefore K \propto \cos^{2}(\omega t + \phi) \end{matrix}$$

Create a free account to view solution

View Solution Free
Topic: SHM·Practice all SHM questions

More SHM Questions