SHMMedium
Question
For a simple pendulum, having time period $T$, the variation of kinetic energy (K.E.) with time $(t)$ is represented by:
Options
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B.
C.
D.
Solution
Sol. [Key Concept: Simple pendulum — KE varies as sin² over time] Kinetic energy, $K = \frac{1}{2}mv^{2}$
$$\begin{matrix} & \ = \frac{1}{2}mA^{2}\omega^{2}\cos^{2}(\omega t + \phi) \\ & \ \therefore K \propto \cos^{2}(\omega t + \phi) \end{matrix}$$
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