Momentum and CollisionHard

Question

An isolated particle of mass m is moving in horizontal plane (x-y), along x-axis, at a certain height above the ground. It suddenly explodes into two fragment of masses m/4 and 3m/4. An instant later, the smaller fragment is at y = + 15 cm. The larger fragment at this instant is at

Options

A.y = - 5 cm
B.y = + 20 cm
C.y = + 5 cm
D.y = - 20 cm

Solution

Before explosion, particle was moving along x-axis i.e., it has no y-component of velocity. Therefore, the centre of mass will be not move in y-direction or we can say yCM = 0.
Now,           yCM
Therefore,       0 =
or       y = - 5 cm.

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