Ionic EquilibriumEasy
Question
Heat of neutralisation of oxalic acid is -25.4 K cal mol-1 using strong base NaOH. Hence enthalpy change of the process :-
H2C2O4 ⇋ 2H+ + C2O42- is :-
H2C2O4 ⇋ 2H+ + C2O42- is :-
Options
A.2.0 kcal
B.-11.8 kcal
C.1.0 kcal
D.-1.0 kcal
Solution
Heat of neutralisation of diboric acid H2C2O4 would have been - 27.4 kcal but some heat evolved is used in dissociation of weak acid H2C2O4
Heat used for dissociation = 27.4 - 25.4 = 2kcal
Heat used for dissociation = 27.4 - 25.4 = 2kcal
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