Chemical BondingHard
Question
Approximate size of the nucleus 6428N of is :-
Options
A.3.5 fm
B.4.5 fm
C.5.5 fm
D.2.5 fm
Solution
rn = r0A1/3 = 1.4 × 641/3 fm = 5.6 fm ≈ 5.5 fm
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