Mole ConceptHard
Question
CH3-CO-CH3(g) ⇋ CH3-CH3 (g) + CO(g)
Initial pressure of CH3COCH3 is 100 mm. When equilibrium is set up mole fraction of CO(g) is 1/3, hence Kp is :-
Initial pressure of CH3COCH3 is 100 mm. When equilibrium is set up mole fraction of CO(g) is 1/3, hence Kp is :-
Options
A.100 mm
B.50 mm
C.25 mm
D.150 mm
Solution
CH3COCH3(g) ⇋ CH3-CH3(g) + CO (g)
100 0 0
100 - x x x
total = 100 + x
Now mole fraction of CO =
x = 50
CH3COCH3(g) ⇋ CH3-CH3(g) + CO(g)
50 50 50
Kp =
= 50 mm
100 0 0
100 - x x x
total = 100 + x
Now mole fraction of CO =
x = 50
CH3COCH3(g) ⇋ CH3-CH3(g) + CO(g)
50 50 50
Kp =
= 50 mmCreate a free account to view solution
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