Solid StateHard
Question
How many unit cell are present in a cube-shaped ideal crystal of NaCl of mass 1.00 gm. [Atomic masses : Na = 23, Cl = 35.5]
Options
A.2.57 × 1021 unit cells
B.5.14 × 1021 unit cells
C.1.25 × 1021 unit cells
D.1.71 × 1021 unit cells
Solution
No. of moles in 1g = 
So. number of molecules =
× NA
∵ 4 molecules are present in one unit cell of NaCl.
∴
molecule, are present in = 
= 2.57 × 1021 unit cell of N
So. number of molecules =
× NA ∵ 4 molecules are present in one unit cell of NaCl.
∴
molecule, are present in = = 2.57 × 1021 unit cell of N
Create a free account to view solution
View Solution FreeMore Solid State Questions
Gold crystallizes with FCC lattice for which the side length of the unit cell is 5.0 Å. If the density of gold is 10.5 g...In a crystal at 827°C one out of 1010 lattice site is found to be vacant but at 927°C, one out of 2 × 109 lattice sites ...Which of the following is an intrinsic or thermodynamic defect?...MgAl2O4, is found in the Spinal structure in which O2- ions constitute CCP lattice, Mg2+ ions occupy 1/8th of the Tetrah...A given metal crystallizes out with a cubic structure having edge length of 361 pm. If there are four metal atoms in one...