Ionic EquilibriumHard
Question
For a sparingly soluble salt ApBq the relationship of its solubility product (Ls) with its solubility (S) is :
Options
A.Ls = Spq. pp. qq
B.Ls = Sp + q. pq. qp
C.Ls = Sp + q. pp. qq
D.Ls = Spq. (p.q)p + q
Solution
ApBq ⇋ pAq+ + qBp- (S = solubility)
pS qS
L2 = (pS)p . (qS)q
L2 = pp . qq (S)p+q
pS qS
L2 = (pS)p . (qS)q
L2 = pp . qq (S)p+q
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