Ionic EquilibriumHard
Question
The pH of 10-8 M solution of HCl in water is :
Options
A.8
B.- 8
C.between 7 and 8
D.between 6 and 7
Solution
H2O ⇋ H+ + OH-
(10-8 + a) a
a is the concentration of [H+] furnished by the dissociation of H2O.
Kw = [H+][OH-]
10-14 = (10-8 + a)(a)
a = 0.95 × 10-7
[H+] = 10-8 + 0.95 × 10-7
= 1.05 × 10-7
pH = - log10 1.05 × 10-7
= 6.9788
(10-8 + a) a
a is the concentration of [H+] furnished by the dissociation of H2O.
Kw = [H+][OH-]
10-14 = (10-8 + a)(a)
a = 0.95 × 10-7
[H+] = 10-8 + 0.95 × 10-7
= 1.05 × 10-7
pH = - log10 1.05 × 10-7
= 6.9788
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