Ionic EquilibriumHard
Question
A solution is a mixture of 0.05 M KCI and 0.05 M NaI. The concentration of I- in the solution when AgCI just starts to precipitate is equal to: (KSPAgCI = 10-10 M2 ; KSPAgI = 4 × 10-16 M2)
Options
A.4 × 10-6 M
B.2 × 10-8 M
C.2 × 10-7 M
D.8 × 10-15 M
Solution
For AgCI precipitation [Ag+] =
= 2 × 10-9
For AgI precipitation [Ag+] =
= 8 × 10-15
Thus AgI will precipitate first. AgCI will precipitate only when,
[Ag+] = 2 × 10-9; Thus [I-]Left =
= 2 × 10-7 M
For AgI precipitation [Ag+] =
Thus AgI will precipitate first. AgCI will precipitate only when,
[Ag+] = 2 × 10-9; Thus [I-]Left =
Create a free account to view solution
View Solution FreeMore Ionic Equilibrium Questions
Which of the following compounds is not an antacid?...Which is/are correct statements : (a) When 100 ml of 0.1 M NaCN solution is titrated with 0.1 M HCl solution the variati...For two different acids with same concentration...In which of the following solutions, the solubility of AgCN will be greater than that in pure water :Given Ksp(AgCN) = 4...Select the correct statements : 1. pH of NaHCO3 solution can be given by 2. AI3+ ion is amphoteric3. KSP values of metal...